Question
Download Solution PDFFind Young's modulus of a brass rod of diameter 25 mm and length 250 mm which is subjected to a tensile load of 50 kN, when the extension of the rod is equal to 0.3 mm.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Elongation of a circular bar:
Extension of the rod under the axial pull,
Where, P= load applied, L = length of the bar, E = Modulus of elasticity, d = diameter of the bar
Calculation:
Given,
L = 250 mm
δL = 0.3 mm, P = 50 kN, d = 25 mm
⇒ E = 84882.64 MPa
⇒ E = 84.883 GPa or 84.883 GN/m2
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