Find the differentiation of f(x) = 

  1. -a
  2. -acosec2x – (c × cosec x cot x)
  3. -acosec2x + bsec2 c + (c × cosec x cot x)
  4. cosec2x – (c × cosec x cot x)

Answer (Detailed Solution Below)

Option 2 : -acosec2x – (c × cosec x cot x)
Free
UP TGT Hindi FT 1
125 Qs. 500 Marks 120 Mins

Detailed Solution

Download Solution PDF

Concept:

Calculation:

Given: f(x) =  = acot x + b + c cosec x

Now, f'(x) = 

⇒ -acosec2x – (c × cosec x cot x)

∴ The required value is -acosec2x – (c × cosec x cot x)

Latest UP TGT Updates

Last updated on May 6, 2025

-> The UP TGT Exam for Advt. No. 01/2022 will be held on 21st & 22nd July 2025.

-> The UP TGT Notification (2022) was released for 3539 vacancies.

-> The UP TGT 2025 Notification is expected to be released soon. Over 38000 vacancies are expected to be announced for the recruitment of Teachers in Uttar Pradesh. 

-> Prepare for the exam using UP TGT Previous Year Papers.

Hot Links: teen patti rules teen patti gold download teen patti sequence teen patti baaz teen patti customer care number