Find the current across 4 ohm resistance.

Calculation:

Let the potential across the 4Ω  resistor be V_x

Applying KVL across 4Ω  

\(\frac{10-Vx}{3}=\frac{Vx}{4}+\frac{Vx-5}{6}\)

⇒\(40 - 4V_X=3 V_X+2 V_X -10\)

⇒\(V_X=50/9 \) V

Current across 4Ω  resistor = \(\frac{50}{9\times 4}\) A

= 25/18 A