Find the angle between the line  and the plane 2x - 3y + z - 5 = 0 ?

Answer (Detailed Solution Below)

Option 4 :
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Detailed Solution

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Concept:

If θ is the angle between the line  and the plane a2x + by + c2z + d = 0 then

Calculation:

Given: Equation of line is  and equation of plane is 2x - 3y + z - 5 = 0.

As we know that the angle between the line  and the plane a2x + by + c2z + d = 0  is given by: 

Here, a1 = 1, b1 = - 2, c1 = - 3, a2 = 2, b2 = - 3 and c2 = 1.

⇒ a1⋅ a2 + b1 ⋅ b2 + c1 ⋅ c2 = 2 + 6 - 3 = 5

 and 

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