Question
Download Solution PDFযদি α এবং β দ্বিঘাত সমীকরণ (5 + √2) x2 - (4 + √5) x + (8 + 2√5) = 0 -এর মূল হয়, তাহলে 2αβ/ (α + β) এর মান হল:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFদ্বিঘাত সমীকরণের জন্য, ax2 + bx + c = 0, α + β = -b/a এবং αβ = c/a
⇒ এখানে, αβ = (8 + 2√5)/(5 + √2) এবং α + β = (4 + √5)/(5 + √2)
⇒ সুতরাং, 2αβ/ (α + β)
⇒ 2[(8 + 2√5) / (5 + √2)] / [(4 + √5) / (5 + √2)]
⇒ 2 [(8 + 2√5) (4 - √5)] / [(4 + √5) / (4 - √5)]
⇒ 2(32 + 8√5 - 8√5 - 10)/11
⇒ 44/11 = 4
Last updated on Jun 2, 2025
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