Area of right angle triangle having sides 6 cm, 8 cm and 10 cm is:

Concept:

Area of a right angle triangle = \(\frac{1}{2}~\times~base~\times~height\)

Pythagoras theorem: (Hypotenuse)² = (base)² + (height)²

Calculation:

Given:

The sides of a right-angle triangle are 6 cm, 8 cm, and 10 cm

∵ 10² = 8² + 6²

Sides satisfies Pythagoras' theorem.

So, Base = 8 cm, height = 6 cm

Area of right angle triangle = \(\frac{1}{2}~\times~base~\times~height\)

⇒ Area of right angle triangle = \(\frac{1}{2}~\times~8~\times~6 =24 ~cm^2\)