Question
Download Solution PDFAn object of mass 20 kg is lifted to a height of 5 m in 20 sec. The power required will be: (g=10m/s2)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
Power:
- The rate of doing work is called power.
- SI unit of power is the watt.
\(⇒ P=\frac{W}{t}\)
.Where P = power, W = work done and t = time
CALCULATION:
Given m = 20 kg, h = 5 m, t = 20 sec and g = 10 m/sec2
- We know that the work done in lifting a body of mass m to height h is given as,
⇒ W = mgh -----(1)
By equation 1,
⇒ W = 20 × 10 × 5 = 1000 J
- So power required,
\(⇒ P=\frac{W}{t}\)
\(⇒ P=\frac{1000}{20}\)
\(⇒ P=50\,watt\)
- Hence, option 1 is correct.
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