An object of mass 150 kg is accelerated uniformly from a velocity of 10 ms-1 to 20 ms-1 in 10 s. Find the magnitude of the force exerted on the object.

  1. 150 J
  2. 200 Kg
  3. 200 N
  4. 150 N

Answer (Detailed Solution Below)

Option 4 : 150 N
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Detailed Solution

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The correct answer is 150 N.

Key Points

CONCEPT:

  • Force: The interaction which after applying on a body changes or try to change the state of rest or state of motion of the body is called force.

Force (F) = Mass (m) × acceleration (a) 

There are three equations of motion:

V = u + at

V2 = u2 + 2 a S

\({\text{S}} = {\text{ut}} + \frac{1}{2}{\text{a}}{{\text{t}}^2}\)

Where, V = final velocity, u = initial velocity, s = distance traveled by the body under motion, a = acceleration of body under motion, and t = time taken by the body under motion.

CALCULATION:

Given that:

mass of the object (m) = 150 kg.

Time taken (t) = 10 sec.

⇒ Initial velocity = 10 m/s.

⇒ Final velocity = 20 m/s.

Use V = u + at

20 = 10 + a × 10

So a = 1 m/s2

Force = m a  = 150 × 1 = 150 N

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