Question
Download Solution PDFA RC beam has cross section \(300 \text{mm} \times 600 \text{mm}\) and is subjected to the following design forces
Bending moment \(=115 \text{KN}- \text{m}\)
Shear force \(=95 \text{KN}- \text{m}\)
Torsional moment \(=45 \text{KN}- \text{m}\)
Determine the equivalent bending moment for which section is to be designed.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
To determine the equivalent bending moment for the RC beam, we can use the following formula: \(M_{eq}=M+\frac{T(1+\frac{D}{b})}{1.7}\)
where: M = bending moment, V = shear force, d = distance from the neutral axis to the point of application of the shear force, and T = torsional moment. For a rectangular section, we can assume d to be half the height of the beam.
Calculation:
Given: M = 115 kN-m; V = 95 kN-m; T = 45 kN-m; D = 0.6 m; b = 0.3 m
\(M_{eq}=115+\frac{45\times (1+\frac{0.6}{0.3})}{1.7}\)
\(M_{eq}=115+79.41=194.41kN-m\)
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