Question
Download Solution PDFA Pelton wheel operates under a head of 40 m and develops shaft power of 800 kW which runs at 500 rpm. Assume the overall efficiency of the Pelton turbine as 80%. Find the flow rate of water. [Density of water = 1000 kg/m3, Acceleration due to gravity = 10 m/s2]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The overall efficiency of the Pelton wheel is given by,
\({η _o} = \frac{{Shaft \;Power}}{{Water\; Power}}\)
Water Power = ρQgH
Calculation:
Given:
Shaft Power = 800 kW, ηo = 0.8, H = 40 m
ρ = 1000 kg/m3, g =10 m/s2
\({η _o} = \frac{{Shaft \;Power}}{{Water\; Power}}\)
\({0.8} = \frac{{800}}{{Water\; Power}}\)
Water Power = 1000 kW
Water Power = ρQgH
1000 × 103 = 1000 × Q × 10 × 40
Q = 2.5 m3/s.
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