A choke coil of inductance Land series resistance R is shunted by a capacitor C. The dynamic impedance of the resonant circuit would be

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WBPSC JE Electrical 2018 (Held on 18th Feb 2018) Official Paper
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  1. \(\rm \frac{R}{LC}\)
  2. \(\rm \frac{C}{LR}\)
  3. \(\rm \frac{L}{RC}\)
  4. \(\rm \frac{1}{RLC}\)

Answer (Detailed Solution Below)

Option 3 : \(\rm \frac{L}{RC}\)
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Detailed Solution

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Dynamic impedance

It is an impedance offered by the network to the source under resonance conditions.

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The input admittance is given by:

\(Y=j\omega C\space +\space {1\over R+j\omega L}\)

\(Y=j\omega C\space +\space ({1\over R+j\omega L}\times {R-j\omega L\over R-j\omega L} )\)

\(Y=j\omega C\space +\space {R-j\omega L\over R^2+(\omega L)^2}\)

\(Y={R\over R^2+(\omega L)^2}+j({\omega C-{\omega L\over R^2+(\omega L)^2}})\).........(i)

At resonance, the imaginary part is zero.

\({\omega C={\omega L\over R^2+(\omega L)^2}}\)

\({\omega L={\omega C (R^2+(\omega L)^2}})\)...........(ii)

Putting the value of equation (ii) in equation (i), we get:

\(Y={RC\over L}\)

\(Z={1\over Y}\)

\(Z=\rm \frac{L}{RC}\)

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