Question
Download Solution PDFA choke coil of inductance Land series resistance R is shunted by a capacitor C. The dynamic impedance of the resonant circuit would be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFDynamic impedance
It is an impedance offered by the network to the source under resonance conditions.
The input admittance is given by:
\(Y=j\omega C\space +\space {1\over R+j\omega L}\)
\(Y=j\omega C\space +\space ({1\over R+j\omega L}\times {R-j\omega L\over R-j\omega L} )\)
\(Y=j\omega C\space +\space {R-j\omega L\over R^2+(\omega L)^2}\)
\(Y={R\over R^2+(\omega L)^2}+j({\omega C-{\omega L\over R^2+(\omega L)^2}})\).........(i)
At resonance, the imaginary part is zero.
\({\omega C={\omega L\over R^2+(\omega L)^2}}\)
\({\omega L={\omega C (R^2+(\omega L)^2}})\)...........(ii)
Putting the value of equation (ii) in equation (i), we get:
\(Y={RC\over L}\)
\(Z={1\over Y}\)
\(Z=\rm \frac{L}{RC}\)
Last updated on Jun 24, 2025
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