A car travelling at a constant speed of 36 km/hr in a circular path of radius 200 m, then normal acceleration and tangential acceleration in m/s² is given by

Concept:

Normal acceleration and tangential acceleration along a curved road is given by

Normal acceleration, \({a_n} = \frac{{{v^2}}}{R}\)

Tangential acceleration, \({a_t} = R\timesα \)

where v is the tangential velocity of the car, R is the radius of the curved road and α is the angular acceleration of the car.

Calculation:

Given:

R = 200 m, v = 36 km/hr = \(36 \times \frac{5}{{18}}\) m/s = 10 m/s, α = 0 (since not mentioned)

Normal acceleration,

\({a_n} = \frac{{{v^2}}}{R} = \frac{{{{10}^2}}}{{200}} = 0.5\;{\rm{m}}/{{\rm{s}}^2}\;\)

Tangential acceleration,

\({a_t} = R\timesα \)

\({a_t} = 200\times0\)

\({a_t} = 0\)

Hence, the value of an = 0.5 m/s2, and at = 0.