Caselet DI MCQ Quiz - Objective Question with Answer for Caselet DI - Download Free PDF

Last updated on Jul 15, 2025

Latest Caselet DI MCQ Objective Questions

Caselet DI Question 1:

Comprehension:

There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?

How much population is educated in 2001 in both the villages together?

  1. 34.44%
  2. 38%
  3. 32% 
  4. 43%

Answer (Detailed Solution Below)

Option 1 : 34.44%

Caselet DI Question 1 Detailed Solution

Given-

Population of Rampur in 2001 = 10000

Population of Mohanpur in 2001 = 8000

Ratio of educated and uneducated population in 2001 in Rampur = 3 : 7

Ratio of educated and uneducated population in 2001 in Mohanpur = 4 : 6

Formula used-

Part of A = Total no × ratio of A / ratio of A + Ratio of B

Percentage of A = share of A × 100 / total share

Calculation -

Educated population in Rampur = 10000 × 3 / 10 = 3000

Educated population in Mohanpur = 8000 × 4 / 10 = 3200

Total population of both villages = 18000

Educated population in both village = 6200

⇒ Percentage of educated population = 6200 × 100 / 18000 = 34 .44%

Hence educated population in both villages is 34.44%

Caselet DI Question 2:

Comprehension:

There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?

What will be the approximate population of Mohanpur in 2003?

  1. 7853
  2. 8500
  3. 8800
  4. 8653

Answer (Detailed Solution Below)

Option 4 : 8653

Caselet DI Question 2 Detailed Solution

Given-

Given population of Mohanpur in 2001 = 8000

Rate of increasing per year = 4%

Formula used-

Population = present population (1 + R / 100) t

Population in 2003 = 8000 (1 + 4 / 100)2 = 8000 (26 / 25 × 26 / 25)

Population in 2003 = 8652 .8

⇒ Population in 2003 = 8653 approx.

Caselet DI Question 3:

Comprehension:

There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?

What will be number of uneducated women in 2001 in Rampur village?

  1. 3000
  2. 32000
  3. 2800
  4. 2400

Answer (Detailed Solution Below)

Option 3 : 2800

Caselet DI Question 3 Detailed Solution

Given-

Population of Rampur in 2001 = 10000

Ratio of men and Women in Rampur = 3 : 2

Ratio of educated and uneducated population in Rampur = 3 : 7

Formula used-

Part of A = Total no × ratio of A / ratio of A + Ratio of B

Calculation -

Number of Women in Rampur = 10000 × 2 / 5 = 4000

Number of uneducated Women = 4000 × 7 / 10 = 2800

Hence no of uneducated women = 2800 in Rampur village.

Caselet DI Question 4:

Comprehension:

There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?

What is the ratio of educated men in Rampur village and Mohanpur village in 2001?

  1. 6 : 7
  2. 45 : 56
  3. 71 : 65
  4. 31 : 30

Answer (Detailed Solution Below)

Option 2 : 45 : 56

Caselet DI Question 4 Detailed Solution

Given -

Population of Rampur in 2001 = 10000

Population of Mohanpur in 2001 = 8000

Ratio of Men and Women in 2001 in Rampur = 3 : 2

Ratio of Men and Women in 2001 in Mohanpur = 7 : 3

Ratio of educated and uneducated population in Rampur in 2001 = 3 : 7

Ratio of educated and uneducated population in Mohanpur in 2001 = 2 : 3

Formula used-

 A : B = A / B

 Part of A = Total no × ratio of A / ratio of A + Ratio of B

Calculation -

No of men in Rampur = 10000 × 3/5  = 6000

No of educated men in Rampur = 6000 × 3 / 10 = 1800

⇒ educated men in Rampur = 1800

Hence no of men in Mohanpur = 8000 × 7 / 10 = 5600

No of men educated in Mohanpur = 5600 × 2 / 5 = 2240

Ratio of educated Men in Rampur : Ratio of educated men in Mohanpur = 1800 : 2240

⇒ 90 : 112

 ⇒ 45 : 56

Caselet DI Question 5:

Comprehension:

Directions: Read the data carefully and answer the following questions. 

Three individuals, A, B, and C, were given a set of questions. They attempted some of them. The number of questions attempted by B is 50% of the total questions he was given. A was given 20 fewer questions than B. C was given 130 questions. The combined number of questions attempted by A and C is 145. The total number of questions given to all three is twice the total number of questions they attempted. Additionally, the number of questions attempted by B and C is the same.

If C scored 70 marks, with 1 mark awarded for each correct answer and a penalty of 1/4th mark for each incorrect answer, how many questions did C answer incorrectly?

  1. 8
  2. 10
  3. 16
  4. 25

Answer (Detailed Solution Below)

Option 3 : 16

Caselet DI Question 5 Detailed Solution

General Solution:

Let:
GA : Questions given to A
GB : Questions given to B
GC : Questions given to C
AA : Questions attempted by A
AB : Questions attempted by B
AC : Questions attempted by C

B attempted 50% of the questions he was given:

AB = 0.5 × GB

A was given 20 fewer questions than B:

GA = GB - 20

C was given 130 questions:

GC = 130

Combined questions attempted by A and C is 145:

AA + AC = 145

Total questions given to all three is twice the total questions they attempted:

GA + GB + GC = 2 × (AA + AB + AC)

Number of questions attempted by B and C is the same:

AB = AC

From Equation 1:

AB = 0.5 × GB

From Equation 3:

GC = 130

From Equation 2:

GA = GB - 20

From Equation 4:

AA + AC = 145

From Equation 5:

GA + GB + GC = 2 × (AA + AB + AC)

Substitute GA = GB - 20 and GC = 130 into Equation 5:

GB - 20 + GB + 130 = 2 × (AA + AB + AC)

Simplify:

2GB + 110 = 2 × (AA + AB + AC)

GB + 55 = AA + AB + AC

From Equation 4:

AA + AC = 145

From Equation 6:

AB = AC

Substitute AB = Ainto GB + 55 = AA + AB + AC:

GB + 55 = AA + AB + AC

GB + 55 = AA + 2AC

From Equation 4:

AA = 145 - AC

Substitute AA = 145 - AC into GB + 55 = AA + 2AC:

GB + 55 = 145 - AC + 2AC

Simplify:

GB + 55 = 145 + AC

GB = 90 + AC

From Equation 1:

AB = 0.5 × GB

From Equation 6:

AB = AC

So:

AC = 0.5 × GB

Substitute AC = 0.5 × Ginto GB = 90 + AC:

GB = 90 + 0.5 × GB

Subtract 0.5 × Gfrom both sides:

0.5 × GB = 90

GB = 180

Now, find AC:

AC = 0.5 × GB = 0.5 × 180 = 90

From Equation 6:

AB = AC = 90

From Equation 4:

AA = 145 - AC = 145 - 90 = 55

From Equation 2:

GA = GB - 20 = 180 - 20 = 160

From Equation 3:

GC = 130

Thus,

Person Given Attempted
A 160 55
B 180 90
C 130 90

 

Calculations:

Let:

x: Number of correct answers by C 

y: Number of incorrect answers by C

C attempted 90 questions:

 

x + y = 90

C scored 70 marks:

x - (1/4)y = 70

From x + y = 90, we can write:

x = 90 - y

Substitute x = 90 - y into the second equation:

(90 - y) - (1/4)y = 70

90 - (5/4)y = 70

(5/4)y = 20

y = 16

Thus, the number of incorrect questions answered by C is 16.

Top Caselet DI MCQ Objective Questions

Comprehension:

Directions: Read the given information carefully and answer the following questions.

A and B invested in a business in the ratio 4 : 5. A invested for 4 months more than B. At the end of year, the total profit earned is Rs. 35000 out of which B earned Rs. 15000. 

What is the ratio of the time period of investment of A and B?

  1. 3 : 2
  2. 5 : 3
  3. 2 : 1
  4. 4 : 1
  5. 5 : 2

Answer (Detailed Solution Below)

Option 2 : 5 : 3

Caselet DI Question 6 Detailed Solution

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Given:

Investment ratio of A and B = 4:5.

Time invested by A = 4 months more than B.

Total profit = Rs. 35000.

Profit earned by B = Rs. 15000.

Formula Used:

Profit share ratio = (Investment × Time) ratio.

Calculation:

Let investment of A = 4x, and B = 5x.

Let time invested by B = t months, then A invested for t + 4 months.

Profit ratio = Profit of A : Profit of B.

From total profit, Profit of A = Rs. 35000 - Rs. 15000 = Rs. 20000.

Profit ratio = 20000 : 15000 = 4 : 3.

Setting up equation from profit ratio:

⇒ (4x × (t + 4)) / (5x × t) = 4 / 3

Removing x as it cancels out:

⇒ (4 × (t + 4)) / (5 × t) = 4 / 3

Cross multiply to solve for t:

⇒ 12 × (t + 4) = 20 × t

⇒ 12t + 48 = 20t

⇒ 8t = 48

⇒ t = 6

Time invested by B = 6 months, and A = 6 + 4 = 10 months.

Time ratio of A to B = 10 months : 6 months = 5 : 3.

The ratio of the time period of investment of A and B is 5:3.

Comprehension:

Directions: Read the given information carefully and answer the following questions.

A and B invested in a business in the ratio 4 : 5. A invested for 4 months more than B. At the end of year, the total profit earned is Rs. 35000 out of which B earned Rs. 15000. 

What is the amount invested by A in the business?

  1. Rs. 16000
  2. Rs. 20000
  3. Rs. 18000
  4. Rs. 22000
  5. Cannot be determined

Answer (Detailed Solution Below)

Option 5 : Cannot be determined

Caselet DI Question 7 Detailed Solution

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Let the amount invested by A and B be 4x and 5x respectively

Let B invested by ‘t’ months

Time of investment of A = t + 4

Profit ratio = 4x × (t + 4) : 5x × t = (4t + 16) : 5t

Now, B’s share:

5t/(4t + 16 + 5t) × 35000 = 15000

35t = 27t + 48

8t = 48

t = 6 months

Period of investment: A = 10 months, B = 6 months 

Amount invested by A = 4x

We cannot determine the value of ‘x’

∴ Amount invested by A cannot be determined.

Here many might mistake 'by the end of year' as one year and solve the question and get it wrong. Note that it is not written 'by the end of one year', since no numerical value of time is given, and with only the ratio given we can not reach a valid conclusion. 

200 students appeared in a specific examination. There were 80 students who failed in Mathematics. 160 students passed in Physics. 30 students failed in Chemistry. 30 students failed in Mathematics and Physics. 15 students failed in Mathematics and Chemistry. 10 students failed in Physics and Chemistry. 100 students passed in all three subjects.

How many students failed in only one subject?

  1. 45
  2. 55
  3. 30
  4. 80

Answer (Detailed Solution Below)

Option 2 : 55

Caselet DI Question 8 Detailed Solution

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Concept used:

n(A U B U C) = n(A) + n (B) + n(c) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C)

Where, n(A U B U C) = no of students failed in all subject

n(A ∩ B ∩ C) = number of total students failed

Calculation:

Total students pass = 100

So, total students fail = 200 - 100 = 100

Students failed in Physics = 200 - 160 = 40

Now,

100 = 80 + 40 + 30 - (15 + 30 + 10) + students failed in all subjects

⇒ students failed in all subjects = 100 - 150 + 55 

⇒ students failed in all subjects 155 - 150 = 5

Again,

Failed in only (M, P) = 30 - 5 = 25

Failed in only (P, C) = 10 - 5 = 5

Failed in only (C, M) = 15 - 5 = 10

So,

Failed in only maths = 80 - (10 + 5 + 25) = 80 - 40 = 40

Failed in only physics = 40 - (25 + 5 + 5) = 40 - 35 = 5

Failed in only chemistry = 30 - (10 + 5 + 5) = 30 - 20 = 10

Thus, total students failed in only one subject = 40 + 5 + 10 = 55

∴ The correct answer is option (2). 

Comprehension:

Directions: Consider the following information and answer the questions based on it

In a group of 75 students, 12 like only cabbage, 15 like only cauliflower, 21 like only carrot, 12 like both carrot and cabbage, 13 like only capsicum and 2 like both capsicum and cauliflower. 

The difference between the people who like carrot and cauliflower is

A. 6

B. 18

C. 16

D. 4

  1. D
  2. A
  3. B
  4. C

Answer (Detailed Solution Below)

Option 4 : C

Caselet DI Question 9 Detailed Solution

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Total number of people who like carrot = 21 + 12 = 33

Total number of people who like cauliflower = 15 + 2 = 17

∴ Required difference = 33 – 17 = 16

Comprehension:

Directions: Read the given information carefully and answer the following questions.

Three streams Arts, Science, and Commerce are offered in 3 colleges A, B, and C.  

(1) There are 1750 students in college A. The number of Commerce students in college A is 400 more than that of in Science in college A. the ratio of the number of students in college A in Arts and Science is 23 : 2.

(2) There are 3250 students in Arts in all colleges. The number of students in Science in all colleges is 37.5% less than that of in Commerce in all colleges.

(3) The number of Arts students in college C is 10% more than that of in college B. the ratio of the number of students in Science in college B to that of in college C is 3 : 4.

(4) The number of students in Commerce in college B is 30% less than that in college A. total number of students in college B is 280 less than that of in college C.

The total number of students in college B is what percent more/less than that of in Science in all colleges?

  1. 106.25%
  2. 141.25%
  3. 118.75%
  4. 96.96%
  5. 105.50%

Answer (Detailed Solution Below)

Option 1 : 106.25%

Caselet DI Question 10 Detailed Solution

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Let the number of students in Arts and Science in college A be 23x and 2x respectively.

⇒ Number of students in Commerce in college A = 400 + 2x

23x + 2x + 400 + 2x = 1750

27x = 1350

x = 50

College A: Arts = 1150, Science = 100, Commerce = 500

Let the number of Commerce students in all colleges be 8y

⇒ Number of Science students in all colleges = 62.5/100 × 8y = 5y

Number of students in Commerce in college B = 70/100 × 500 = 350

⇒ Number of students in Commerce in college C = 8y – (500 + 350)

⇒ 8y – 850

Let the number of students in Arts in college B be z

⇒ Number of students in Arts in college C = 110/100 × z = 1.1z

1150 + z + 1.1z = 3250

2.1z = 2100

z = 1000

Number of students in Science in college B = 3/7 × (5y – 100) = 15y/7 – 300/7

Number of students in Science in college C = 4/7 × (5y – 100) = 20y/7 – 400/7

Now, Total number of students in college B = 1000 + 350 + 15y/7 – 300/7

⇒ 1350 – 300/7 + 15y/7

Total number of students in college C = 1100 + 20y/7 – 400/7 + 8y – 850

⇒ 250 – 400/7 + 20y/7 + 8y

Now,  250 – 400/7 + 20y/7 + 8y – 280 = 1350 – 300/7 + 15y/7

⇒ 1380 + 100/7 = 61y/7

⇒ y = 160

Now, putting the value of y and z, we get

College

Number of students in Arts

Number of students in Science

Number of students in Commerce

A

1150

100

500

B

1000

300

350

C

1100

400

430

 

Total students in college B = 1000 + 300 + 350 = 1650

Total students in Science in all colleges = 100 + 300 + 400 = 800

∴ Required percent = (1650 – 800)/800 × 100 = 106.25%

District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters. For an election, 25% of the rural voters were shifted to the urban area. Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking.

Two candidates, A and B, contested the election. Candidate B swept the urban vote, while Candidate A found favour with the rural voters. Voters who were both honest and hardworking voted for NOTA. How many votes were polled in favour of candidate A, candidate B and NOTA, respectively?

  1. 17875, 14625 and 17500
  2. 19500, 13000 and 17500
  3. 19000, 13500 and 17500
  4. 17000, 15500 and 17500

Answer (Detailed Solution Below)

Option 2 : 19500, 13000 and 17500

Caselet DI Question 11 Detailed Solution

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Given:

District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters.

Calculation:

Total votes = 50000

⇒ Urban votes originally = 20/100 × 50000 = 10000 and Rural votes originally = 80/100 × 50000 = 40000

For election, 25% of the rural voters were shifted to the urban area 

⇒ 25/100 × 40000 = 10000 rural votes shifted to urban area.

⇒ Now, Urban votes = 10000 + 10000 = 20000 and Rural votes = 40000 - 10000 = 30000

Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking.

Voters who were both honest and hardworking voted for NOTA.

∴ Votes swept by NOTA = 35% of urban + 35% of rural =  35/100 × 20000 + 35/100 × 30000 = 17500 

Candidate A found favour with the rural voters, rural voters left = 100% - 35% = 65% of rural voters

∴ Votes swept by A =  65/100 × 30000 = 19500

Candidate B found favour with the urban voters, Urban voters left = 100% - 35% = 65% of urban voters

∴ Votes swept by B =  65/100 × 20000 = 13000

⇒ Votes polled in favor of candidate A, candidate B and NOTA are 19500, 13000 and 17500 respectively

Comprehension:

Directions: Read the following information carefully and answer the given questions:- 

In school, the total number of students is 14,000. On the annual function of the school, 25% of the total boys and 60% of total girls have participated and the number of total girls in the school is equal to the number of boys who have not participated in the function. 

Find the number of boys who have participated in annual function of the school.

  1. 2000
  2. 1500
  3. 1800
  4. 1000
  5. 2500

Answer (Detailed Solution Below)

Option 1 : 2000

Caselet DI Question 12 Detailed Solution

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Given

:

Total number of students = 14,000

Percentage of boys who participated in annual function = 25%

Percentage of girls who participated in annual function = 60%

Number of girls in school = Number of boys who have not participated in function

Concept used:

Total number of boys or girls = Number of those who participated + Number of those who have not participated

Calculation:

Let the number of boys and girls be x and y respectively

Number of boys who have participated in annual function = 25% of x

⇒ 0.25x

Number of boys who have not participated = (x – 0.25x)

⇒ 0.75x

Number of girls in school = y = 0.75x

Now, as per the question

⇒ x + y = 14,000

⇒ x + 0.75x = 14,000

⇒ 1.75x = 14,000

⇒ x = 8000

Number of boys who have participated in annual function = 0.25x

⇒ 0.25 × 8000

⇒ 2000

∴ The number of boys who have participated in annual function is 2000

Comprehension:

Direction: Read the information carefully and answer the following questions:

In a school of 750 students, each student likes atleast one of the three colors- Red, Green and Blue. 109 students like only red color, 150 students like only green color and 125 students like only blue color. The number of students who like red and green colors only is 70% of the students who like only green color. The number of students who like red and blue colors only is 60% of the students who like only blue color. 100 students like all the colors. 

Find the number of students who like green and blue colours only.

  1. 66
  2. 76
  3. 86
  4. 96
  5. 106

Answer (Detailed Solution Below)

Option 3 : 86

Caselet DI Question 13 Detailed Solution

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Given:

Total number of students = 750

The number of students who like red and green colours only  =  70% of 150 students

and The number of students who like red and blue colours only = 60% of 125 students

Calculation:

Let the number of students who like green and blue colours only be a.

Number of students who like red and green colours only = (70/100) × 150

⇒ 105 students

Number of students who like red and blue colours only = (60/100) × 125

⇒ 75 students

Now, The total number of students = 750

⇒ 109 + 150 + 125 + 100 + 105 + 75 + a = 750

⇒ 664 + a = 750

⇒ a = 750 – 664

⇒ a = 86 students

∴ 86 students like both green and blue colors only.

A survey of 170 families, 115 drink Coffee, 110 drink Tea and 130 drink Milk. Also, 85 drink Coffee and Milk, 75 drink Coffee and Tea, 95 drink Tea and Milk, 70 drink all the three. Find How many use Coffee and Milk but not Tea.

  1. 18
  2. 25
  3. 20
  4. 15

Answer (Detailed Solution Below)

Option 4 : 15

Caselet DI Question 14 Detailed Solution

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Given,

Number of families who participate in survey = 170

Number of families who drink Coffee = 115

Number of families who drink Tea = 110

Number of families who drink Milk = 130

Number of families who drink Coffee and Milk = 85

Number of families who drink Coffee and Tea = 75

Number of families who drink Tea and Milk = 95

Number of families who drink Coffee, Milk and Tea = 70

Calculation:

Number of families who drink only Milk and Tea = 95 – 70 = 25

Number of families who drink only Coffee and Milk = 85 – 70 = 15

Comprehension:

Direction: Read the following data carefully and answer the following questions:

There are two villages A and B in a certain district. The population of village A is 35% less than the population of village B. Total population of both villages is 8250. The ratio between adults and children in two villages is 20: 13. The difference between the number of adults and children including two villages is 1750. In village A, the number of adults is 60% more than the number of children. While in village B, the number of adults is 1.5 times the number of children.

Find the difference between the number of adults in village B and the number of  children village B.

  1. 1200
  2. 800
  3. 1500
  4. 1000
  5. 900

Answer (Detailed Solution Below)

Option 4 : 1000

Caselet DI Question 15 Detailed Solution

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Let the population of village A and Village B be A and B respectively.

⇒ A + B = 8250

⇒ 65B/100 + B = 8250

⇒ B = 5000

⇒ A = 3250

Let adults of village A and Village B be P and Q respectively while children of village A and Village B be S and T respectively.

⇒ P + S = 3250

⇒ 160S/100 + S = 3250

S = 1250 = children of village A

P = 2000 = adults of village A

⇒ Q + T = 5000

⇒ 1.5T + T = 5000

T = 2000 = children of village B

Q = 3000 = adults of village B

Required difference = 3000 – 2000 = 1000

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