Caselet DI MCQ Quiz - Objective Question with Answer for Caselet DI - Download Free PDF
Last updated on Jul 15, 2025
Latest Caselet DI MCQ Objective Questions
Caselet DI Question 1:
Comprehension:
There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?
How much population is educated in 2001 in both the villages together?
Answer (Detailed Solution Below)
Caselet DI Question 1 Detailed Solution
Given-
Population of Rampur in 2001 = 10000
Population of Mohanpur in 2001 = 8000
Ratio of educated and uneducated population in 2001 in Rampur = 3 : 7
Ratio of educated and uneducated population in 2001 in Mohanpur = 4 : 6
Formula used-
Part of A = Total no × ratio of A / ratio of A + Ratio of B
Percentage of A = share of A × 100 / total share
Calculation -
Educated population in Rampur = 10000 × 3 / 10 = 3000
Educated population in Mohanpur = 8000 × 4 / 10 = 3200
Total population of both villages = 18000
Educated population in both village = 6200
⇒ Percentage of educated population = 6200 × 100 / 18000 = 34 .44%
Hence educated population in both villages is 34.44%
Caselet DI Question 2:
Comprehension:
There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?
What will be the approximate population of Mohanpur in 2003?
Answer (Detailed Solution Below)
Caselet DI Question 2 Detailed Solution
Given-
Given population of Mohanpur in 2001 = 8000
Rate of increasing per year = 4%
Formula used-
Population = present population (1 + R / 100) t
Population in 2003 = 8000 (1 + 4 / 100)2 = 8000 (26 / 25 × 26 / 25)
Population in 2003 = 8652 .8
⇒ Population in 2003 = 8653 approx.
Caselet DI Question 3:
Comprehension:
There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?
What will be number of uneducated women in 2001 in Rampur village?
Answer (Detailed Solution Below)
Caselet DI Question 3 Detailed Solution
Given-
Population of Rampur in 2001 = 10000
Ratio of men and Women in Rampur = 3 : 2
Ratio of educated and uneducated population in Rampur = 3 : 7
Formula used-
Part of A = Total no × ratio of A / ratio of A + Ratio of B
Calculation -
Number of Women in Rampur = 10000 × 2 / 5 = 4000
Number of uneducated Women = 4000 × 7 / 10 = 2800
Hence no of uneducated women = 2800 in Rampur village.
Caselet DI Question 4:
Comprehension:
There is a village, Rampur. The population of village is 10000. In 2001 the ratio of man and women is 3 : 2 and ratio of educated and uneducated population is 3 : 7 for each of men and women. The population of village is increasing 5 % every year and rate of educated people is increasing 3 % every year. There is another village Mohanpur population of village is 8000 and increasing at the rate of 4 % per year, ratio of men and women is 7 : 3 and educated and uneducated is 2 : 3 for each of men and women in 2001. The population of Educated people is increasing with the rate of 3%. Answer the question given below?
What is the ratio of educated men in Rampur village and Mohanpur village in 2001?
Answer (Detailed Solution Below)
Caselet DI Question 4 Detailed Solution
Given -
Population of Rampur in 2001 = 10000
Population of Mohanpur in 2001 = 8000
Ratio of Men and Women in 2001 in Rampur = 3 : 2
Ratio of Men and Women in 2001 in Mohanpur = 7 : 3
Ratio of educated and uneducated population in Rampur in 2001 = 3 : 7
Ratio of educated and uneducated population in Mohanpur in 2001 = 2 : 3
Formula used-
A : B = A / B
Part of A = Total no × ratio of A / ratio of A + Ratio of B
Calculation -
No of men in Rampur = 10000 × 3/5 = 6000
No of educated men in Rampur = 6000 × 3 / 10 = 1800
⇒ educated men in Rampur = 1800
Hence no of men in Mohanpur = 8000 × 7 / 10 = 5600
No of men educated in Mohanpur = 5600 × 2 / 5 = 2240
Ratio of educated Men in Rampur : Ratio of educated men in Mohanpur = 1800 : 2240
⇒ 90 : 112
⇒ 45 : 56
Caselet DI Question 5:
Comprehension:
Directions: Read the data carefully and answer the following questions.
Three individuals, A, B, and C, were given a set of questions. They attempted some of them. The number of questions attempted by B is 50% of the total questions he was given. A was given 20 fewer questions than B. C was given 130 questions. The combined number of questions attempted by A and C is 145. The total number of questions given to all three is twice the total number of questions they attempted. Additionally, the number of questions attempted by B and C is the same.
If C scored 70 marks, with 1 mark awarded for each correct answer and a penalty of 1/4th mark for each incorrect answer, how many questions did C answer incorrectly?
Answer (Detailed Solution Below)
Caselet DI Question 5 Detailed Solution
General Solution:
Let:
GA : Questions given to A
GB : Questions given to B
GC : Questions given to C
AA : Questions attempted by A
AB : Questions attempted by B
AC : Questions attempted by C
B attempted 50% of the questions he was given:
AB = 0.5 × GB
A was given 20 fewer questions than B:
GA = GB - 20
C was given 130 questions:
GC = 130
Combined questions attempted by A and C is 145:
AA + AC = 145
Total questions given to all three is twice the total questions they attempted:
GA + GB + GC = 2 × (AA + AB + AC)
Number of questions attempted by B and C is the same:
AB = AC
From Equation 1:
AB = 0.5 × GB
From Equation 3:
GC = 130
From Equation 2:
GA = GB - 20
From Equation 4:
AA + AC = 145
From Equation 5:
GA + GB + GC = 2 × (AA + AB + AC)
Substitute GA = GB - 20 and GC = 130 into Equation 5:
GB - 20 + GB + 130 = 2 × (AA + AB + AC)
Simplify:
2GB + 110 = 2 × (AA + AB + AC)
GB + 55 = AA + AB + AC
From Equation 4:
AA + AC = 145
From Equation 6:
AB = AC
Substitute AB = AC into GB + 55 = AA + AB + AC:
GB + 55 = AA + AB + AC
GB + 55 = AA + 2AC
From Equation 4:
AA = 145 - AC
Substitute AA = 145 - AC into GB + 55 = AA + 2AC:
GB + 55 = 145 - AC + 2AC
Simplify:
GB + 55 = 145 + AC
GB = 90 + AC
From Equation 1:
AB = 0.5 × GB
From Equation 6:
AB = AC
So:
AC = 0.5 × GB
Substitute AC = 0.5 × GB into GB = 90 + AC:
GB = 90 + 0.5 × GB
Subtract 0.5 × GB from both sides:
0.5 × GB = 90
GB = 180
Now, find AC:
AC = 0.5 × GB = 0.5 × 180 = 90
From Equation 6:
AB = AC = 90
From Equation 4:
AA = 145 - AC = 145 - 90 = 55
From Equation 2:
GA = GB - 20 = 180 - 20 = 160
From Equation 3:
GC = 130
Thus,
Person | Given | Attempted |
---|---|---|
A | 160 | 55 |
B | 180 | 90 |
C | 130 | 90 |
Calculations:
Let:
x: Number of correct answers by C
y: Number of incorrect answers by C
C attempted 90 questions:
x + y = 90
C scored 70 marks:
x - (1/4)y = 70
From x + y = 90, we can write:
x = 90 - y
Substitute x = 90 - y into the second equation:
(90 - y) - (1/4)y = 70
90 - (5/4)y = 70
(5/4)y = 20
y = 16
Thus, the number of incorrect questions answered by C is 16.
Top Caselet DI MCQ Objective Questions
Comprehension:
Directions: Read the given information carefully and answer the following questions.
A and B invested in a business in the ratio 4 : 5. A invested for 4 months more than B. At the end of year, the total profit earned is Rs. 35000 out of which B earned Rs. 15000.
What is the ratio of the time period of investment of A and B?
Answer (Detailed Solution Below)
Caselet DI Question 6 Detailed Solution
Download Solution PDFGiven:
Investment ratio of A and B = 4:5.
Time invested by A = 4 months more than B.
Total profit = Rs. 35000.
Profit earned by B = Rs. 15000.
Formula Used:
Profit share ratio = (Investment × Time) ratio.
Calculation:
Let investment of A = 4x, and B = 5x.
Let time invested by B = t months, then A invested for t + 4 months.
Profit ratio = Profit of A : Profit of B.
From total profit, Profit of A = Rs. 35000 - Rs. 15000 = Rs. 20000.
Profit ratio = 20000 : 15000 = 4 : 3.
Setting up equation from profit ratio:
⇒ (4x × (t + 4)) / (5x × t) = 4 / 3
Removing x as it cancels out:
⇒ (4 × (t + 4)) / (5 × t) = 4 / 3
Cross multiply to solve for t:
⇒ 12 × (t + 4) = 20 × t
⇒ 12t + 48 = 20t
⇒ 8t = 48
⇒ t = 6
Time invested by B = 6 months, and A = 6 + 4 = 10 months.
Time ratio of A to B = 10 months : 6 months = 5 : 3.
The ratio of the time period of investment of A and B is 5:3.
Comprehension:
Directions: Read the given information carefully and answer the following questions.
A and B invested in a business in the ratio 4 : 5. A invested for 4 months more than B. At the end of year, the total profit earned is Rs. 35000 out of which B earned Rs. 15000.
What is the amount invested by A in the business?
Answer (Detailed Solution Below)
Caselet DI Question 7 Detailed Solution
Download Solution PDFLet the amount invested by A and B be 4x and 5x respectively
Let B invested by ‘t’ months
Time of investment of A = t + 4
Profit ratio = 4x × (t + 4) : 5x × t = (4t + 16) : 5t
Now, B’s share:
5t/(4t + 16 + 5t) × 35000 = 15000
35t = 27t + 48
8t = 48
t = 6 months
Period of investment: A = 10 months, B = 6 months
Amount invested by A = 4x
We cannot determine the value of ‘x’
∴ Amount invested by A cannot be determined.
Here many might mistake 'by the end of year' as one year and solve the question and get it wrong. Note that it is not written 'by the end of one year', since no numerical value of time is given, and with only the ratio given we can not reach a valid conclusion.
200 students appeared in a specific examination. There were 80 students who failed in Mathematics. 160 students passed in Physics. 30 students failed in Chemistry. 30 students failed in Mathematics and Physics. 15 students failed in Mathematics and Chemistry. 10 students failed in Physics and Chemistry. 100 students passed in all three subjects.
How many students failed in only one subject?
Answer (Detailed Solution Below)
Caselet DI Question 8 Detailed Solution
Download Solution PDFConcept used:
n(A U B U C) = n(A) + n (B) + n(c) - n(A ∩ B) - n(B ∩ C) - n(C ∩ A) + n(A ∩ B ∩ C)
Where, n(A U B U C) = no of students failed in all subject
n(A ∩ B ∩ C) = number of total students failed
Calculation:
Total students pass = 100
So, total students fail = 200 - 100 = 100
Students failed in Physics = 200 - 160 = 40
Now,
100 = 80 + 40 + 30 - (15 + 30 + 10) + students failed in all subjects
⇒ students failed in all subjects = 100 - 150 + 55
⇒ students failed in all subjects = 155 - 150 = 5
Again,
Failed in only (M, P) = 30 - 5 = 25
Failed in only (P, C) = 10 - 5 = 5
Failed in only (C, M) = 15 - 5 = 10
So,
Failed in only maths = 80 - (10 + 5 + 25) = 80 - 40 = 40
Failed in only physics = 40 - (25 + 5 + 5) = 40 - 35 = 5
Failed in only chemistry = 30 - (10 + 5 + 5) = 30 - 20 = 10
Thus, total students failed in only one subject = 40 + 5 + 10 = 55
∴ The correct answer is option (2).
Comprehension:
Directions: Consider the following information and answer the questions based on it
In a group of 75 students, 12 like only cabbage, 15 like only cauliflower, 21 like only carrot, 12 like both carrot and cabbage, 13 like only capsicum and 2 like both capsicum and cauliflower.
The difference between the people who like carrot and cauliflower is
A. 6
B. 18
C. 16
D. 4
Answer (Detailed Solution Below)
Caselet DI Question 9 Detailed Solution
Download Solution PDFTotal number of people who like carrot = 21 + 12 = 33
Total number of people who like cauliflower = 15 + 2 = 17
∴ Required difference = 33 – 17 = 16
Comprehension:
Directions: Read the given information carefully and answer the following questions.
Three streams Arts, Science, and Commerce are offered in 3 colleges A, B, and C.
(1) There are 1750 students in college A. The number of Commerce students in college A is 400 more than that of in Science in college A. the ratio of the number of students in college A in Arts and Science is 23 : 2.
(2) There are 3250 students in Arts in all colleges. The number of students in Science in all colleges is 37.5% less than that of in Commerce in all colleges.
(3) The number of Arts students in college C is 10% more than that of in college B. the ratio of the number of students in Science in college B to that of in college C is 3 : 4.
(4) The number of students in Commerce in college B is 30% less than that in college A. total number of students in college B is 280 less than that of in college C.
The total number of students in college B is what percent more/less than that of in Science in all colleges?
Answer (Detailed Solution Below)
Caselet DI Question 10 Detailed Solution
Download Solution PDFLet the number of students in Arts and Science in college A be 23x and 2x respectively.
⇒ Number of students in Commerce in college A = 400 + 2x
23x + 2x + 400 + 2x = 1750
27x = 1350
x = 50
College A: Arts = 1150, Science = 100, Commerce = 500
Let the number of Commerce students in all colleges be 8y
⇒ Number of Science students in all colleges = 62.5/100 × 8y = 5y
Number of students in Commerce in college B = 70/100 × 500 = 350
⇒ Number of students in Commerce in college C = 8y – (500 + 350)
⇒ 8y – 850
Let the number of students in Arts in college B be z
⇒ Number of students in Arts in college C = 110/100 × z = 1.1z
1150 + z + 1.1z = 3250
2.1z = 2100
z = 1000
Number of students in Science in college B = 3/7 × (5y – 100) = 15y/7 – 300/7
Number of students in Science in college C = 4/7 × (5y – 100) = 20y/7 – 400/7
Now, Total number of students in college B = 1000 + 350 + 15y/7 – 300/7
⇒ 1350 – 300/7 + 15y/7
Total number of students in college C = 1100 + 20y/7 – 400/7 + 8y – 850
⇒ 250 – 400/7 + 20y/7 + 8y
Now, 250 – 400/7 + 20y/7 + 8y – 280 = 1350 – 300/7 + 15y/7
⇒ 1380 + 100/7 = 61y/7
⇒ y = 160
Now, putting the value of y and z, we get
College |
Number of students in Arts |
Number of students in Science |
Number of students in Commerce |
A |
1150 |
100 |
500 |
B |
1000 |
300 |
350 |
C |
1100 |
400 |
430 |
Total students in college B = 1000 + 300 + 350 = 1650
Total students in Science in all colleges = 100 + 300 + 400 = 800
∴ Required percent = (1650 – 800)/800 × 100 = 106.25%
District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters. For an election, 25% of the rural voters were shifted to the urban area. Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking.
Two candidates, A and B, contested the election. Candidate B swept the urban vote, while Candidate A found favour with the rural voters. Voters who were both honest and hardworking voted for NOTA. How many votes were polled in favour of candidate A, candidate B and NOTA, respectively?
Answer (Detailed Solution Below)
Caselet DI Question 11 Detailed Solution
Download Solution PDFGiven:
District XYZ has 50,000 voters; out of them, 20% are urban voters and 80% rural voters.
Calculation:
Total votes = 50000
⇒ Urban votes originally = 20/100 × 50000 = 10000 and Rural votes originally = 80/100 × 50000 = 40000
For election, 25% of the rural voters were shifted to the urban area
⇒ 25/100 × 40000 = 10000 rural votes shifted to urban area.
⇒ Now, Urban votes = 10000 + 10000 = 20000 and Rural votes = 40000 - 10000 = 30000
Out of the voters in both rural and urban areas, 60% are honest, 70% are hardworking, and 35% are both honest and hardworking.
Voters who were both honest and hardworking voted for NOTA.
∴ Votes swept by NOTA = 35% of urban + 35% of rural = 35/100 × 20000 + 35/100 × 30000 = 17500
Candidate A found favour with the rural voters, rural voters left = 100% - 35% = 65% of rural voters
∴ Votes swept by A = 65/100 × 30000 = 19500
Candidate B found favour with the urban voters, Urban voters left = 100% - 35% = 65% of urban voters
∴ Votes swept by B = 65/100 × 20000 = 13000
⇒ Votes polled in favor of candidate A, candidate B and NOTA are 19500, 13000 and 17500 respectively
Comprehension:
Directions: Read the following information carefully and answer the given questions:-
In school, the total number of students is 14,000. On the annual function of the school, 25% of the total boys and 60% of total girls have participated and the number of total girls in the school is equal to the number of boys who have not participated in the function.
Find the number of boys who have participated in annual function of the school.
Answer (Detailed Solution Below)
Caselet DI Question 12 Detailed Solution
Download Solution PDF:
Total number of students = 14,000
Percentage of boys who participated in annual function = 25%
Percentage of girls who participated in annual function = 60%
Number of girls in school = Number of boys who have not participated in function
Concept used:
Total number of boys or girls = Number of those who participated + Number of those who have not participated
Calculation:
Let the number of boys and girls be x and y respectively
Number of boys who have participated in annual function = 25% of x
⇒ 0.25x
Number of boys who have not participated = (x – 0.25x)
⇒ 0.75x
Number of girls in school = y = 0.75x
Now, as per the question
⇒ x + y = 14,000
⇒ x + 0.75x = 14,000
⇒ 1.75x = 14,000
⇒ x = 8000
Number of boys who have participated in annual function = 0.25x
⇒ 0.25 × 8000
⇒ 2000
∴ The number of boys who have participated in annual function is 2000
Comprehension:
Direction: Read the information carefully and answer the following questions:
In a school of 750 students, each student likes atleast one of the three colors- Red, Green and Blue. 109 students like only red color, 150 students like only green color and 125 students like only blue color. The number of students who like red and green colors only is 70% of the students who like only green color. The number of students who like red and blue colors only is 60% of the students who like only blue color. 100 students like all the colors.
Find the number of students who like green and blue colours only.
Answer (Detailed Solution Below)
Caselet DI Question 13 Detailed Solution
Download Solution PDFGiven:
Total number of students = 750
The number of students who like red and green colours only = 70% of 150 students
and The number of students who like red and blue colours only = 60% of 125 students
Calculation:
Let the number of students who like green and blue colours only be a.
Number of students who like red and green colours only = (70/100) × 150
⇒ 105 students
Number of students who like red and blue colours only = (60/100) × 125
⇒ 75 students
Now, The total number of students = 750
⇒ 109 + 150 + 125 + 100 + 105 + 75 + a = 750
⇒ 664 + a = 750
⇒ a = 750 – 664
⇒ a = 86 students
∴ 86 students like both green and blue colors only.
A survey of 170 families, 115 drink Coffee, 110 drink Tea and 130 drink Milk. Also, 85 drink Coffee and Milk, 75 drink Coffee and Tea, 95 drink Tea and Milk, 70 drink all the three. Find How many use Coffee and Milk but not Tea.
Answer (Detailed Solution Below)
Caselet DI Question 14 Detailed Solution
Download Solution PDFGiven,
Number of families who participate in survey = 170
Number of families who drink Coffee = 115
Number of families who drink Tea = 110
Number of families who drink Milk = 130
Number of families who drink Coffee and Milk = 85
Number of families who drink Coffee and Tea = 75
Number of families who drink Tea and Milk = 95
Number of families who drink Coffee, Milk and Tea = 70
Calculation:
Number of families who drink only Milk and Tea = 95 – 70 = 25
Number of families who drink only Coffee and Milk = 85 – 70 = 15Comprehension:
Direction: Read the following data carefully and answer the following questions:
There are two villages A and B in a certain district. The population of village A is 35% less than the population of village B. Total population of both villages is 8250. The ratio between adults and children in two villages is 20: 13. The difference between the number of adults and children including two villages is 1750. In village A, the number of adults is 60% more than the number of children. While in village B, the number of adults is 1.5 times the number of children.
Find the difference between the number of adults in village B and the number of children village B.
Answer (Detailed Solution Below)
Caselet DI Question 15 Detailed Solution
Download Solution PDFLet the population of village A and Village B be A and B respectively.
⇒ A + B = 8250
⇒ 65B/100 + B = 8250
⇒ B = 5000
⇒ A = 3250
Let adults of village A and Village B be P and Q respectively while children of village A and Village B be S and T respectively.
⇒ P + S = 3250
⇒ 160S/100 + S = 3250
S = 1250 = children of village A
P = 2000 = adults of village A
⇒ Q + T = 5000
⇒ 1.5T + T = 5000
T = 2000 = children of village B
Q = 3000 = adults of village B
Required difference = 3000 – 2000 = 1000