Latus Rectum MCQ Quiz in বাংলা - Objective Question with Answer for Latus Rectum - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Apr 15, 2025

পাওয়া Latus Rectum उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Latus Rectum MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Latus Rectum MCQ Objective Questions

Top Latus Rectum MCQ Objective Questions

Latus Rectum Question 1:

Let the eccentricity of an ellipse 1 is reciprocal to that of the hyperbola 2x2 – 2y2 = 1. If the ellipse intersects the hyperbola at right angles, then square of length of the latus-rectum of the ellipse is ______________. 

Answer (Detailed Solution Below) 0 - 2

Latus Rectum Question 1 Detailed Solution

Calculation: 

Since the curves intersect each other orthogonally

The ellipse and the hyperbola are confocal

⇒ 

For ellipse aeE = 1

 Length of L.R 

Hence, the correct answer is 2.

Latus Rectum Question 2:

Find the eccentricity of the ellipse in which length of minor axis is equal to one-fourth of the distance between their foci. 

Answer (Detailed Solution Below)

Option 1 :

Latus Rectum Question 2 Detailed Solution

Answer (1) 

Sol. 

2b = (ae) ⇒ 4b = ae

b2 = a2 - a2e2

b2 a- 16b2

17ba2

e = 

Latus Rectum Question 3:

Let the length of a latus rectum of an ellipse  be 10. If its eccentricity is the minimum value of the function , t ∈ R, then a2 + b2 is equal to : 

  1. 125
  2. 126
  3. 120
  4. 115

Answer (Detailed Solution Below)

Option 2 : 126

Latus Rectum Question 3 Detailed Solution

Calculation: 

Length of LR =  .....(1)

⇒ 

Min value of  

⇒ 

 ......(2)

From (1) & (2)

⇒ 

∴ a2 + b2 = 81 +45 = 126

Hence, the correct answer is Option 2.

Latus Rectum Question 4:

The length of the latus-rectum of the ellipse, whose foci are (2, 5) and (2, –3) and eccentricity is  , is

Answer (Detailed Solution Below)

Option 4 :

Latus Rectum Question 4 Detailed Solution

Calculation:

 

Center C = 

Distance between foci: 

⇒ 2c = 

⇒ c = 4

Also e = a/c ⇒ a = c/e = 

Now ba− c25 − 16 9

⇒ b = 3

Length of latus rectum =  

Hence, the correct answer is Option 4.

Latus Rectum Question 5:

What is the sum of the major and minor axes of the ellipse whose eccentricity is 4/5 and length of latus rectum is 14.4 unit?

  1. 32 unit
  2. 48 unit
  3. 64 unit
  4. None of the above
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : 64 unit

Latus Rectum Question 5 Detailed Solution

Concept:

Standard equation of an ellipse:  (a > b)

Coordinates of foci = (± ae, 0)

Eccentricity (e) =  ⇔ a2e2 = a2 – b2

Length of latus rectum = 

Length of major axis =2a and Length of minor axis = 2b

 

Calculation: 

Here,  e = 4/5 =

Squaring both sides, we get

16/25 = 

∴ (b2 / a2) = 1 - 16/25 =  9/25 ....(1)

 

Latus rectus 2b2 / a = 14.4

⇒ b2 / a = 7.2

Puting above value in (1),

 7.2/ a = 9/25

⇒ a = 20

Now, b2 = 7.2 × 20 = 144

⇒ b = 12

 

Sum of major and minor axes = 2a + 2b

= 2(20) + 2(12)

= 64 

Hence, option (3) is correct.

Latus Rectum Question 6:

What is the length of the latus rectum of the ellipse 25x2 + 16y2 = 400 ?

  1. 25/2
  2. 25/4
  3. 16/5
  4. 32/5
  5. None of the above

Answer (Detailed Solution Below)

Option 4 : 32/5

Latus Rectum Question 6 Detailed Solution

Concept:

Equation

 (a > b)

  (a

Length of Latus rectum

 

Calculation:

25x2 + 16y2 = 400

Comparing, with standard equation: a = 4 ; b = 5

Since ( a

Latus Rectum Question 7:

The length of latus rectum of the ellipse 3x2 + y2 -12x + 2y + 1 = 0 is

  1. 12
  2. None of the above

Answer (Detailed Solution Below)

Option 3 :

Latus Rectum Question 7 Detailed Solution

Concept:

Standard Equation of ellipse: 

Length of latus rectum = 2b2/a, when a > b and 2a2/b, when a

Calculation:

3x2 + y2 -12x + 2y + 1 = 0

⇒ 3(x2 - 4x + 4) – 12 + (y2 + 2y + 1) = 0

⇒ 3(x – 2)2 – 12 + (y + 1)2 = 0

⇒ 3(x – 2)2 + (y + 1)2 = 12

                                  (Divide by 12)

∴ a2 = 22 and b2 = (2√3)2

Here a

So, length of latus rectum = 2a2/b

units

Hence, option (3) is correct.

Latus Rectum Question 8:

If the latus rectum of an ellipse is equal to half of the minor axis, then what is its eccentricity?

  1. 2 / √3
  2. 1 / √3
  3. √3 / 2
  4. 1 / √2
  5. None of the above

Answer (Detailed Solution Below)

Option 3 : √3 / 2

Latus Rectum Question 8 Detailed Solution

Concept:

The equation of ellipse is b)\)

length of Latus rectum of ellipse = 

Length of minor axis = 2b.

 eccentricity = 

Calculations:

Given, the latus rectum of an ellipse is equal to half of the minor axis.

Suppose, the equation of ellipse is 

length of Latus rectum of ellipse = 

Length of minor axis = 2b.

Given, the latus rectum of an ellipse is equal to half of the minor axis

⇒ 

⇒ 

If the equation of ellipse is  then eccentricity = 

⇒ 

⇒ e = 

If the latus rectum of an ellipse is equal to half of the minor axis, then what is its eccentricity e = 

 

Latus Rectum Question 9:

Let the foci of a hyperbola be (1, 14) and (1, –12). If it passes through the point (1, 6), then the length of its latus-rectum is :

  1. None of the above

Answer (Detailed Solution Below)

Option 3 :

Latus Rectum Question 9 Detailed Solution

Calculation

 

be = 13, b = 5

a2 = b2 (e2 – 1)

= b2 e2 – b2

= 169 – 25 = 144

Hence option 3 is correct

Latus Rectum Question 10:

Consider an ellipse, whose centre is at the origin and its major axis is along the x-axis. If its eccentricity is and the distance between its foci is , then the area (in sq. units) of the quadrilateral inscribed in the ellipse, with the vertices as the vertices of the ellipse, is.

Answer (Detailed Solution Below)

Option 3 :

Latus Rectum Question 10 Detailed Solution

The required area is in the shape of kite.

Area of kite

Now,


Hot Links: teen patti sequence teen patti master new version teen patti master apk download