Question
Download Solution PDFWhich of the following is a pair of isotones?
This question was previously asked in
HP TGT (Non-Medical) TET 2018 Official Paper
Answer (Detailed Solution Below)
Option 2 : 6C13, 7N14
Free Tests
View all Free tests >
HP JBT TET 2021 Official Paper
150 Qs.
150 Marks
150 Mins
Detailed Solution
Download Solution PDFConcept:
- Isotones are atoms or nuclei which have an equal number of neutrons.
- 17Cl37 and 19K39 both have the same number of neutrons.
- Isobars are Atoms of a chemical element that have the same atomic mass but a different atomic number.
- Isotopes are Atoms of a chemical element that have the same atomic number but a different atomic mass.
Explanation:
In 6C13, 7N14
For 6C13
No of proton = 6
No of proton + No of neutron = 13
No of neutron = 13 - 6 = 7
For 7N14:
No of proton = 7
No of proton + No of neutron = 14
No of neutron = 14 - 7 = 7
Thus, we conclude that 6C13, 7N14 are isotones.
Additional Information
Pair | p + n | p | n |
7N14, 8O16 | 14, 16 | 7, 8 | 7, 8 |
6C13, 7N14 | 13, 14 | 6, 7 | 7, 7 |
6C12, 6C14 | 12, 14 | 6, 6 | 6, 8 |
18Ar39, 20Ca40 | 39, 40 | 18, 20 | 21, 20 |
Last updated on Jul 9, 2025
-> The HP TET Admit Card has been released for JBT TET and TGT Sanskrit TET.
-> HP TET examination for JBT TET and TGT Sanskrit TET will be conducted on 12th July 2025.
-> The HP TET June 2025 Exam will be conducted between 1st June 2025 to 14th June 2025.
-> Graduates with a B.Ed qualification can apply for TET (TGT), while 12th-pass candidates with D.El.Ed can apply for TET (JBT).
-> To prepare for the exam solve HP TET Previous Year Papers. Also, attempt HP TET Mock Tests.