Question
Download Solution PDFWhat is the slope of normal to the curve y = 2x3 - 5x2 + x - 2 at the point (1, -1)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The slope of the tangent to a curve y = f(x) is m =
The slope of the normal =
Calculation:
Given curve y = 2x3 - 5x2 + x - 2
Differentiating the equation wrt x
Slope at the point (1, -1)
The slope of the normal (m') =
m' =
The slope of the normal to the curve at the point (1, -1) is 1/3.
∴ Option 2 is correct
Last updated on Jul 16, 2025
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