Question
Download Solution PDFWhat is the dimension of the dynamic viscosity (μ)?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
According to Newton's law of viscosity, shear stress is directly proportional to the rate of angular deformation (shear strain) or velocity gradient across the flow.
where, τ = shear stress, μ = absolute or dynamic viscosity, du/dy = velocity gradient ⇒ dα/dt = rate of angular deformation (shear-strain).
Units of Dynamic viscosity:
∴ the unit of dynamic viscosity in SI unit is Ns/m2 or Pa-s.
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