Question
Download Solution PDFComprehension
The following table shows the details about (i) the number of students studying in five different classes A-E of a school, and (ii) participating neither in chess nor in carrom (iii) the ratio of students who participate in Chess to Carrom. The remaining students play either chess or carrom. Based on the data in the table answer questions:
Class-wise Participation in Games
|
Class |
Total Number |
Number of Students |
Ratio of Students |
|
A |
420 |
119 |
4 ∶ 3 |
|
B |
330 |
88 |
7 ∶ 4 |
|
C |
240 |
110 |
8 ∶ 5 |
|
D |
125 |
45 |
2 ∶ 3 |
|
E |
390 |
130 |
8 ∶ 5 |
What is the average of number of students participating in Carrom from D and Chess from A?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe number of students participating in Chess from A is (420-119) x 4/7 = 172.
The number of students participating in Carrom from D is (125-45) x 3/5 = 48
Therefore, the average the number of students participating in Carrom from D and Chess from A is (172 + 48)/2
⇒ 220/2 = 110.
Last updated on Jul 17, 2025
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