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The following table shows the details about (i) the number of students studying in five different classes A-E of a school, and (ii) participating neither in chess nor in carrom (iii) the ratio of students who participate in Chess to Carrom. The remaining students play either chess or carrom. Based on the data in the table answer questions:

Class-wise Participation in Games

Class

Total Number
of Students

Number of Students
without participation
in both the games

Ratio of Students
participating in
Chess to Carrom

A

420

119

4 ∶ 3

B

330

88

7 ∶ 4

C

240

110

8 ∶ 5

D

125

45

2 ∶ 3

E

390

130

8 ∶ 5

What is the average of number of students participating in Carrom from D and Chess from A?

This question was previously asked in
UGC NET Paper 1: Held on 22th Oct 2022 Shift 1
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  1. 110
  2. 130
  3. 146
  4. 125

Answer (Detailed Solution Below)

Option 1 : 110
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Detailed Solution

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The number of students participating in Chess from A is (420-119) x 4/7 = 172.

The number of students participating in Carrom from D is (125-45) x 3/5 = 48

Therefore, the average the number of students participating in Carrom from D and Chess from A is (172 + 48)/2

⇒  220/2 = 110.

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