Question
Download Solution PDFThe velocity field of a two - dimentional, incompressible flow is given by
\(\vec{V}=2 \sinh x ̂{i}+v(x, y) ̂{j}\)
where î and ĵ denote the unit vector in x and y direction, respectively. If v(x,0) = cosh x, then (0, -1) is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
The velocity field of a two-dimensional, incompressible flow is given by,
\(\vec{V}=2 \sinh x \hat{i}+V(x, y) \hat{j}\)
and V(x, 0) = coshx,
For an incompressible flow, ∇ . \(\vec{V}\) = 0
⇒ \(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}=0\)
= 2coshx + \(\frac{\partial v}{\partial y}\) = 0
⇒ \(\frac{\partial v}{\partial y}\) = -2coshx
⇒ \(\int \partial v=\int-2 \cosh x \cdot \partial y\)
V = -2y . coshx + f(x)
For, V(x, 0) = coshx
⇒ -2y × coshx + f(x) = coshx
⇒ f(x) = coshx (at x, 0)
⇒ V = -2 . y × coshx + coshx
V = (1 - 2y) × coshx
V(0, - 1) = [1 - {2 × (-1)}] × cosh(0) = 3
Last updated on Feb 19, 2024
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