Question
Download Solution PDFThe value of current limiting resistor for a stack of 4 LED's connected in series will be ______ if the LED's are 3 V, 3 mA and DC source is 15 V.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Source voltage = 15 V
Voltage of LED = 3 V
Current of LED = 3 mA
Now,
The given circuit can be drawn as
The current through the LED circuit must be 3 mA and the voltage drop across them is 3 V each.
Therefore, by applying KVL, we get,
15 – R (3 mA) - 3 - 3 - 3 - 3 = 0
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