Question
Download Solution PDFThe relation between the radius \((R)\) and degree \((D )\) of a curve is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
The relation between the radius (R, in feet) and the degree of curve (D, in degrees) for a simple circular curve is given by the formula:
\(R=\frac{1719}{D}\)
- This is commonly used in railway and highway alignment design when the degree of curve is defined based on a chord length of 100 feet.
- The formula provides an easy way to convert between the degree of curve and the corresponding radius of curvature.
Additional Information
Degree of Curve (D):
-
The degree of curve is defined as the central angle subtended by a chord of fixed length, typically 100 feet in standard practice.
-
It represents the sharpness of a curve — a larger degree of curve indicates a sharper curve, while a smaller degree indicates a flatter curve.
-
It is used widely in geometric design of roads and railways for laying out curves in the field and in design drawings.
-
The degree of curve provides a convenient way to express curvature without needing to specify the radius directly.
Radius of Curve (R):
-
The radius is the distance from the center of the circle to any point on the curve. It directly determines the curvature — a smaller radius means a sharper curve.
-
Knowing the radius helps in calculating transition curves, vehicle dynamics, and super-elevation requirements for safe turning.
-
In practice, curves with larger radii are preferred for higher-speed routes to reduce centrifugal force and increase comfort.
Last updated on Jul 1, 2025
-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website.
-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).
-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27.
-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering.
-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025.
-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025
-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.
-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.
-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.