Question
Download Solution PDFComprehension
Consider the following for the four (04) items that follow:
The frequency distribution of height of students of a class is given below:
Height (in cm | Number of Students |
160-162 | 12 |
162-164 | 15 |
164-166 | 24 |
166-168 | 13 |
The height which occurs most frequently in the class is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Given the frequency distribution of height of students:
Height (in cm) | Number of Students |
---|---|
160–162 | 12 |
162–164 | 15 |
164–166 | 24 |
166–168 | 13 |
The class interval with the highest frequency is 164–166, with 24 students.
The formula for calculating the mode for grouped data is:
\( \text{Mode} = L + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h \)
Where:
L: Lower boundary of the modal class = 164
f1: Frequency of the modal class = 24
f0: Frequency of the class before the modal class = 15
f2: Frequency of the class after the modal class = 13
h: Class width = 2
Substituting the values into the formula:
\( \text{Mode} = 164 + \left( \frac{24 - 15}{2(24) - 15 - 13} \right) \times 2 \)
\( = 164 + \left( \frac{9}{48 - 28} \right) \times 2 \)
\( = 164 + \left( \frac{9}{20} \right) \times 2 \)
\( = 164 + 0.9 \)
\( = 164.9 \)
∴ The mode is approximately 164.9 cm.
Hence, the correct answer is Option 4.
Last updated on Jul 8, 2025
->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.
->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.