The equation of the plane perpendicular to the yz-plane and passing through the points (1, - 2, 4) and (3, - 4, 5) is

Question

Question

This question was previously asked in

RPSC 2nd Grade Mathematics (Held on 30th June 2017) Official Paper

Answer 1

Concept Used:

Equation of plane in given by

where, is the normal vector to the plane and is a vector of any point in the plane.

Calculation:

Since plane parsing through (1, -2, 4) and (3, -4, 5)

vector in the direction of the plane is:

and x-axis is perpendicular to yz-plane and the direction vector of x -axis is .

Normal vector of plane

Let be a point in the plane.

plane parses through (1, -2, 4)

Hence, the required equation y + 2z = 6.