Question
Download Solution PDFThe current flowing through 61 Ω resistor is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFKirchoff's Current Law
According to KCL the sum of incoming and outgoing current at a node is equal to zero.
ΣI = 0
Assuming the direction of incoming current to be -ve and outgoing +ve.
Applying KCL at Node A:
- 15 + IR + 2IR = 0
IR = 5 A
Additional Information
Kirchoff's Voltage Law
It states that the algebraic sum of potential drops in a closed circuit is zero.
ΣV = 0
−V + I R1 + I R2 = 0
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