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The coefficient of correlation between two variables X and Y is 0.48. The covariance is 36. The variance of X is 16. The standard deviation of Y is:

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SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )
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  1. 10.15
  2. 13.32
  3. 16.5
  4. 18.75

Answer (Detailed Solution Below)

Option 4 : 18.75
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Detailed Solution

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Given

σx = √16 = 4

r = 0.48

Covariance = ∑xy/N = 36

Fomula

Covariance = ∑xy/N

r = ∑xy/N.σx × σy

Calculation

According to question

⇒ 0.48 = 36/4 × σy

⇒ σy = 9/0.48

∴ The standard deviation of y(σy) is 18.75

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