The bandwidth occupied by an 8 PSK modulated signal, where each of the I, Q and C data streams which form the n-tuple IQC toggle at a rate 200 Mbps, is:

This question was previously asked in
ISRO Scientist Electronics 2024 Official Paper
View all ISRO Scientist Papers >
  1. 600 MHz
  2. 200 MHz
  3. 400 MHz
  4. 133.33 MHz

Answer (Detailed Solution Below)

Option 3 : 400 MHz
Free
ISRO Scientist/Engineer Fluid Mechanics Mock Test
20 Qs. 20 Marks 25 Mins

Detailed Solution

Download Solution PDF

Concept:

For an M-ary PSK (M-PSK) system, the symbol rate (baud rate) is:

Where:

  • Rb is the total bit rate
  • is the modulation order

 

The minimum bandwidth required (Nyquist Bandwidth) is: B = RS for ideal conditions

Given:

  • M = 8 (8-PSK)
  • (since I, Q, and C streams each toggle at 200 Mbps)
     

Calculation:

(accounting for both sidebands)

Hence, the correct option is C

Latest ISRO Scientist Updates

Last updated on Jun 24, 2025

-> ISRO Scientist Engineering apply online 2025 link has been activated (ISRO:ICRB:03(CEPO):2025).

-> A total of 39 vacancies are announced for the ISRO recruitment in Civil, RAC and other disciplines

-> ISRO Scientist Engineering recruitment 2025 notification has been released for 320 vacancies. The last date to fill ISRO application form is June 16 (Advt No. ISRO:ICRB:02(EMC):2025).

-> ISRO Scientist Engineer recruitment 2025 for 31 vacancies has been released. 

->ISRO Scientist recruitment 2025 notification has been released. 

->The last date to apply for ISRO scientist recruitment 2025 is May 30 ( Advt.No. ISRO:ICRB:01:(EMC):2025). 

->Candidates with BE/BTech degree in the respective discipline can only apply for ISRO Scientist recruitment 2025. 

-> Candidates can refer ISRO Scientist previous year paper to prepare for the exam. 

Hot Links: teen patti customer care number teen patti jodi teen patti master plus real cash teen patti teen patti comfun card online