x2 - \(\frac{1}{x^2}\) = 4 \(\sqrt2\) எனில் x4 - \(\frac{1}{x^4}\) இன் மதிப்பு என்ன?

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SSC CGL 2023 Tier-I Official Paper (Held On: 27 Jul 2023 Shift 2)
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  1. 16\(\sqrt2\)
  2. 8\(\sqrt2\)
  3. 24\(\sqrt2\)
  4. 32\(\sqrt2\)

Answer (Detailed Solution Below)

Option 3 : 24\(\sqrt2\)
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Detailed Solution

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கொடுக்கப்பட்டது: -

x2 -1/x2 = 4√2

பயன்படுத்தப்படும் சூத்திரம்:-

(A + B)2 = A2 + B2 + 2AB

(A2 - B2) = (A+ B) (A - B)

கணக்கீடு:-

இருபக்கமும் வர்க்கப்படுத்தவும்

⇒ (x -1/x2)2 = (4√2 )2 

⇒ x4 + 1/x4 - 2 = 32 

 x4 + 1/x4  = 34

இரு பக்கமும் 2 ஐ கூட்டவும் 

 x4 + 1/x4 + 2 = 34 +2  

⇒ (
x + 1/x2)2 = 62 

⇒ (x + 1/x2) = 6 ....(1)

கேள்வியின்படி,  

 x4 - 1/x4  =  (x + 1/x2) (x -1/x2

⇒ (4√2) × 6 = 24√ 2   

∴ எனவே தேவையான பதில் 24√ 2.
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