Question
Download Solution PDFSuppose in the First Come First Served Disk Scheduling Algorithm the order of request is (90, 150, 50, 140, 30, 20) and the current position of read/write head is 40, then the total distance covered by the disk ann would be
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is Option 3) 520.
Key Points
- First Come First Served (FCFS) Disk Scheduling Algorithm serves the requests in the order they arrive.
- Given:
- Initial head position = 40
- Request queue = (90, 150, 50, 140, 30, 20)
- We calculate the total distance moved by the disk head step-by-step:
From | To | Distance |
---|---|---|
40 | 90 | 50 |
90 | 150 | 60 |
150 | 50 | 100 |
50 | 140 | 90 |
140 | 30 | 110 |
30 | 20 | 10 |
Total Distance | 50 + 60 + 100 + 90 + 110 + 10 = 520 |
Additional Information
- FCFS Characteristics:
- Simple to implement
- Processes requests in the order of arrival
- Does not optimize seek time
- Other disk scheduling algorithms:
- SSTF (Shortest Seek Time First): Chooses the request closest to current head position
- SCAN: Moves head in one direction, servicing requests in order until end is reached, then reverses
- LOOK: Like SCAN, but stops at last request instead of going to the end of disk
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