Select the set in which the numbers are related in the same way as are the numbers in the following sets :  

{3, 5, 1}, (4, 10,2}

The logic followed in the given sets is:

Logic: 2nd number = 1st numbe × 3rd number + 2 

i.e., B = (A × C) + 2

Let's verify this logic with the given sets:

For {3, 5, 1}:

→ A = 3, C = 1

→ B = (3 × 1) + 2 = 3 + 2 = 5

For {4, 10, 2}:

→ A = 4, C = 2

→ B = (4 × 2) + 2 = 8 + 2 = 10

Option 1) {5, 6, 1}

→ A = 5, C = 1

→ B = (5 × 1) + 2 = 5 + 2 = 7

→ Given B is 6. Since 7 ≠ 6, this option does NOT follow the logic.

Option 2) {7, 3, 8}

→ A = 7, C = 8

→  B = (7 × 8) + 2 = 56 + 2 = 58

→ Given B is 3. Since 58 ≠ 3, this option does NOT follow the logic.

Option 3) {8, 34, 2}

→ A = 8, C = 2

→ B = (8 × 2) + 2 = 16 + 2 = 18

→ Given B is 34. Since 18 ≠ 34, this option does NOT follow the logic.

Option 4) {9, 10, 3}

→ A = 9, C = 3

→ B = (9 × 3) + 2 = 27 + 2 = 29

→ Given B is 10. Since 29 ≠ 10, this option does NOT follow the logic.