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Rate of evaporation of water from a mixture of milk and water in sunlight is 2.5L/hour. At 10:00 AM quantity of milk was 90 liters more than the water and at 4:00 PM same day, ratio of milk to water becomes 8 : 1, then milk will be what percent of total quantity of mixture at 8:00 PM on same day? (Consider sunlight till 8:00 PM)

  1. 96%
  2. 84%
  3. 88%
  4. 92%

Answer (Detailed Solution Below)

Option 1 : 96%
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Detailed Solution

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Let quantity of milk and water at 10:00 AM is ‘x + 90’ and ‘x’ respectively.

Quantity of water vaporized from 10:00 AM to 4:00 PM = 2.5 × 6 = 15 liters

According to the question:

x + 90 = 8x – 120

7x = 210

x = 30

Quantity of milk at 8:00 PM = (x + 90) = 120 liters

Quantity of water at 8:00 PM = x – 2.5 × 10 = 30 – 25 = 5 liters

Required percent = (120/125) × 100 = 96%

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