22x - 10 × 2x + 16 = 0 चे मूळ काय आहे?

This question was previously asked in
RRB Group D 19 Sept 2022 Shift 3 Official Paper
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  1. 1, 3
  2. 1, 8
  3. 2, 8
  4. 2, 3

Answer (Detailed Solution Below)

Option 1 : 1, 3
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RRB Group D Full Test 1
100 Qs. 100 Marks 90 Mins

Detailed Solution

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दिलेले आहे:

22x - 10 × 2x + 16 = 0

गणना:

घटक तयार करण्यासाठी मधल्या संज्ञांचे विभाजन करणे,

⇒ 22x – 8.2x – 2.2x + 16 = 0

⇒ 2x(2x – 8) – 2(2x – 8) = 0

⇒ (2x – 2)(2x – 8) = 0

आता आपल्याकडे आहे 2x = 2 आणि 2x = 8

⇒ 2x = 21 आणि 2x = 23

दोन्ही मूल्यांची तुलना केल्यास, आपल्याला x = 1 किंवा x = 3 मिळेल.

म्हणून, समीकरणाची मुळे 1 आणि 3 आहेत.

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