Question
Download Solution PDFदोन पूरक कोनांपैकी मोठा कोन लहान कोनापेक्षा 50° जास्त आहे. लहान कोन (अंशांमध्ये) आहे:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिले आहे:
दोन पूरक कोनांपैकी मोठा कोन लहान कोनापेक्षा 50º जास्त आहे.
लहान कोन = xº मानू.
मोठा कोन = (x + 50)º.
वापरलेले सूत्र:
लहान कोन + मोठा कोन = 180º
गणना:
पूरक कोनांची बेरीज 180º असते.
x + (x + 50) = 180
⇒ 2x + 50 = 180
⇒ 2x = 130
⇒ x = 65
योग्य उत्तर पर्याय (3) आहे.
Last updated on Jul 17, 2025
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