Question
Download Solution PDFR अनुक्रमे 10 किमी/तास, 9 किमी/तास, ...., पहिल्या तासात 1 किमी/तास, दुसऱ्या तासात, इत्यादी वेगाने 10 तास धावतो. तर त्याचा सरासरी वेग _______ किमी/तास आहे.
Answer (Detailed Solution Below)
Detailed Solution
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धावण्याच्या वेळा = [प्रत्येक 10 तासांसाठी 1 तास]
वेग = [10, 9, 8, 7, 6, 5, 4, 3, 2, 1] किमी/तास
संकल्पना:
सरासरी वेग = एकूण अंतर / एकूण वेळ
गणना:
⇒ एकूण वेळ = 10 तास
⇒ एकूण अंतर = प्रत्येक तासातील अंतरांची बेरीज
= प्रत्येक तासाची बेरीज (वेग x वेळ)
= 10 × 1 + 9 × 1 + ... + 1 × 1 = 55 किमी
⇒ सरासरी वेग = 55 किमी/10 तास = 5.5 किमी/तास
त्यामुळे, R चा सरासरी वेग 5.5 किमी/तास आहे.
Last updated on Jul 8, 2025
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