Question
Download Solution PDFकिरण एका 90 मीटर लांबीच्या पूलात पोहतो. तो दोन मिनिटांत एका टोकापासून दुसऱ्या टोकापर्यंत पोहून व परत त्याच सरळ मार्गाने दोनदा परत येऊन 360 मीटर पोहतो. तर किरणचा सरासरी वेग शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिल्याप्रमाणे,
किरणला 360 मीटर अंतर कापण्यास लागलेला वेळ = 2 मिनिटे
संकल्पना:
सरासरी गति = एकूण अंतर/एकूण वेळ
सरासरी वेग = विस्थापन/घेतलेला वेळ
जेव्हा, विस्थापन = सुरवातीचे टोक व शेवटचे टोक यातले अंतर
गणना:
∵ किरण एका टोकापासून दुसऱ्या टोकापर्यंत पोहतो आणि पुन्हा सुरुवातीच्या टोकाकडे येतो.
⇒ विस्थापन = 90 – 90 + 90 – 90 = 0 मीटर
1 मिनिट = 60 सेकंद
∴ किरणचा सरसरी वेग = 0/120 = 0 मीसे-1
Last updated on Jun 30, 2025
-> The RRB NTPC Admit Card 2025 has been released on 1st June 2025 on the official website.
-> The RRB Group D Exam Date will be soon announce on the official website. Candidates can check it through here about the exam schedule, admit card, shift timings, exam patten and many more.
-> A total of 1,08,22,423 applications have been received for the RRB Group D Exam 2025.
-> The RRB Group D Recruitment 2025 Notification was released for 32438 vacancies of various level 1 posts like Assistant Pointsman, Track Maintainer (Grade-IV), Assistant, S&T, etc.
-> The minimum educational qualification for RRB Group D Recruitment (Level-1 posts) has been updated to have at least a 10th pass, ITI, or an equivalent qualification, or a National Apprenticeship Certificate (NAC) granted by the NCVT.
-> This is an excellent opportunity for 10th-pass candidates with ITI qualifications as they are eligible for these posts.
-> The selection of the candidates is based on the CBT, Physical Test, and Document Verification.
-> Prepare for the exam with RRB Group D Previous Year Papers.