Question
Download Solution PDFएक आयत 48 सेमी लांब आणि 14 सेमी रुंद आहे. जर कर्ण लांब बाजूने θ कोन बनवतो, तर (sec θ + cosec θ) किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
एक आयत 48 सेमी लांब आणि 14 सेमी रुंद आहे
वापरलेले सूत्र:
sec θ = कर्ण/पाया
cosec θ = कर्ण/पर्पेंडिक्युला
पायथागोरस प्रमेय
(कर्ण)2 = (लंब)2 + (पाया)2
गणना:
त्रिकोण ABC काटकोन त्रिकोण आहे:
कर्ण = AC = x =
येथे,
Sec θ = AC/AB = 50/48
Cosec θ = AC/BC = 50/14
त्यामुळे,
(sec θ + cosec θ) = (50/48) + (50/14) = 1550/336 = 775/168
∴ sec θ + cosec θ चे मूल्य 775/168 आहे
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