Question
Download Solution PDFवर्तुळ एका चौकोन ABCD मध्ये कोरलेले आहे, जे AB, BC, CD आणि DA या बाजूंना अनुक्रमे P, Q, R आणि S येथे स्पर्श करते. जर AS = 6 सेमी, BC = 12 सेमी, आणि CR = 5 सेमी, तर AB ची लांबी (सेमी मध्ये) किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
AS = 6 सेमी
BC = 12 सेमी
CR = 5 सेमी
वापरलेली संकल्पना:
जर एका बाह्य बिंदूपासून, दोन स्पर्शरेषा वर्तुळात काढल्या गेल्या असतील तर त्यांना समान स्पर्शिका विभाग असतात.
गणना:
⇒ CR = CQ = 5 सेमी
⇒ BQ = BC – CQ
⇒ (12 – 5) = 7 सेमी
⇒ BQ = BP = 7 सेमी....(1)
⇒ AS = AP = 6 सेमी....(2)
समीकरण (1) आणि (2) एकत्र केल्यावर, आपल्याला मिळते
⇒ (7 + 6)
⇒ 13 सेमी
∴ AB ची लांबी 13 सेमी आहे
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