In a rolling operation, the thickness of a rectangular piece is reduced from t₁ to t₂. The radius of both the rolls are equal to R. The angle of bite (θ) will be given by:

Explanation:

t₁ = thickness of bar before rolling

t₂ = thickness of bar after rolling

R = Radius of Rollers

θ = ∠ AOC = Bite angle

Bite Angle:

It is the angle subtended at the centre by the contact arc of roll-work.

Here BC = B’C’

∴ t₁ – t₂ = BC + B’C’ ⇒ 2BC

Alternate method:

t₁ - t₂ = 2R (1 - cosθ)