Answer (Detailed Solution Below)

Option 2 :
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PYST 1: SSC CGL - General Awareness (Held On : 20 April 2022 Shift 2)
25 Qs. 50 Marks 10 Mins

Detailed Solution

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Given:

tan2 θ + tan4 θ = 1

Concept used:

tan2 θ + 1 = sec2 θ

Calculation:

⇒ tan2 θ + tan4 θ = 1

⇒ tan2 θ (1 + tan2 θ) = 1

⇒ tan2 θ × sec2 θ = 1

⇒ tan2 θ = 1/sec2 θ = cos2 θ 

Now put the value of tan2 θ in the equation:

⇒ tan2 θ + tan4 θ = 1

⇒ tan2 θ + (tan2)2 θ = 1

⇒ cos2 θ + (cos2)2 θ = 1

⇒ cos2 θ + cos4 θ = 1

∴ The correct option is 2.

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