Question
Download Solution PDFIf the magnetic bearing of the Sun at a certain place in the Southern Hemisphere during noon is 336° 29’, then the magnetic declination at that place is __________.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Magnetic bearing of sun at noon = 336° 29'
At Noon, the sun is exactly over the time median of the place. Thus true bearing of the line joining the sun and the place is either 0° and 360° if it is to the north and 180°/360° if it is to the south of the place.
Magnetic bearing of sun at noon = 182°30'
True bearing = 360°
True bearing = M.B + declination
360° - 336° 29'' = declination
So,
declination = 23° 31’ or declination = 2° 31' E
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