Question
Download Solution PDFIf the atmospheric pressure at sea level is 10.144 N/cm², what will be the absolute pressure at the height of 3 km from sea level? [Pressure variation may be assumed to follow the hydrostatic law, density of air is assumed constant as 1.2 kg/m³]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Using hydrostatic law:
\( P = P_0 - \rho g h \)
Given:
- \( P_0 = 10.144 \, \text{N/cm}^2 = 101440 \, \text{N/m}^2 \)
- \( \rho = 1.2 \, \text{kg/m}^3 \)
- \( g = 9.81 \, \text{m/s}^2 \)
- \( h = 3000 \, \text{m} \)
Calculation:
\( \Delta P = \rho g h = 1.2 \cdot 9.81 \cdot 3000 = 35316 \, \text{N/m}^2 \)
\( P = 101440 - 35316 = 66124 \, \text{N/m}^2 = 6.612 \, \text{N/cm}^2 \)
Last updated on Jul 15, 2025
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