If tan x = , where x lies in the second quadrant, what is the value of sin x − cot x?

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 24 Jul 2023 Shift 2)
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Answer (Detailed Solution Below)

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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
25 Qs. 50 Marks 12 Mins

Detailed Solution

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Given

tan x = -12/5

Concept

tan x = Perpendicular/base

Sin x = Perpendicular/hypotenuse

Calculation

tan x = -12/5 = Perpendicular/base

P = 12 and B = - 5

H2 = P2 + B2

H2 = 144 + 25

H2 = 169

H = 13

⇒ sin x − cot x

⇒ P/H + B/P   ...(since cot is also negative in second quadrant)

⇒ (P2 + BH)PH

⇒ (144 + 65)/156

⇒ 209/156

The value is 209/156.

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