If P, Q, R be whole numbers and P : Q : R = 2 : 3 : 4 and P2 + Q2 + R2 = 11600, then P + Q - R =

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BSSC Group D Official Paper (Held On: 11 May, 2025)
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  1. 20
  2. 15
  3. 16
  4. 18

Answer (Detailed Solution Below)

Option 1 : 20
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BSSC Group D (कार्यालय परिचारी) ST (Class 8th) 1: General Awareness
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Detailed Solution

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Given:

P : Q : R = 2 : 3 : 4

P2 + Q2 + R2 = 11600

Formula used:

Let P = 2k, Q = 3k, R = 4k

P2 + Q2 + R2 = (2k)2 + (3k)2 + (4k)2

Calculation:

(2k)2 + (3k)2 + (4k)2 = 11600

⇒ 4k2 + 9k2 + 16k2 = 11600

⇒ 29k2 = 11600

⇒ k2 = 11600 ÷ 29

⇒ k2 = 400

⇒ k = √400

⇒ k = 20

P = 2k = 2 × 20 = 40

Q = 3k = 3 × 20 = 60

R = 4k = 4 × 20 = 80

P + Q - R = 40 + 60 - 80

⇒ P + Q - R = 20

∴ The correct answer is option 1.

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-> The examination was conducted on 11th May 2025.

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