Question
Download Solution PDFHow many 2k × 8 ROM chips would be required to build a 16k × 8 memory system?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
ROM- Read-Only Memory (ROM) chips are non-volatile memory that generally contains instructions for "booting" the computer (i.e. loading the operating system when the computer starts up).
For 2n × m ROM chips we have:
1. n address lines.
2. m bit data lines.
The total capacity of ROM chips required = Number of ROM chips × Capacity of single ROM chip
Analysis:
Given, the capacity of single-chip = 2k × 8
Required capacity = 16k × 8
Number of ROM chips required =
= 8
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