Question
Download Solution PDFसमांतर श्रेढ़ी (A.P.) 4, 9, 14, 19, … का कौन-सा पद 109 है?
This question was previously asked in
Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
Answer (Detailed Solution Below)
Option 2 : 22
Free Tests
View all Free tests >
Bihar STET Paper 1 Social Science Full Test 1
11.8 K Users
150 Questions
150 Marks
150 Mins
Detailed Solution
Download Solution PDFदिया गया है:
अंतिम पद = an = 109
प्रयुक्त अवधारणा:
an = a + (n - 1)d
an = nवाँ पद
a = प्रथम पद
d = समांतर श्रेढ़ी के दो पदों के बीच अंतर
गणना:
दी गई समांतर श्रेढ़ी में,
a = 4
d = 9 - 4 = 5
⇒ 109 = 4 + (n - 1)5
⇒ 109 - 4 = 5n - 5
⇒ 105 + 5 = 5n
⇒ 5n = 110
⇒ n = 22
∴ 109, समांतर श्रेढ़ी का 22वाँ पद है।
Last updated on Jul 3, 2025
-> The Bihar STET 2025 Notification will be released soon.
-> The written exam will consist of Paper-I and Paper-II of 150 marks each.
-> The candidates should go through the Bihar STET selection process to have an idea of the selection procedure in detail.
-> For revision and practice for the exam, solve Bihar STET Previous Year Papers.