Question
Download Solution PDFके धनात्मक पूर्णांक हलों की संख्या कितनी है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंप्रत्यय:
समीकरण x + y + z = n के धनात्मक पूर्णांक हलों की संख्या संयोजन सूत्र द्वारा दी जाती है:
हलों की संख्या = C(n - 1, k - 1), जहाँ k चरों की संख्या है।
प्रयुक्त सूत्र:
C(n, r) = n! / [r! × (n - r)!]
गणना:
यहाँ, n = 5 और k = 3 है।
हलों की संख्या है:
⇒ C(5 - 1, 3 - 1) = C(4, 2)
⇒ C(4, 2) = 4! / [2! × (4 - 2)!]
⇒ C(4, 2) = 24 / [2 × 2]
⇒ C(4, 2) = 6
सही उत्तर विकल्प 3 है।
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