अनुक्रम 25, -125, 625, -3125, …… का nवाँ पद क्या है?

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NDA (Held On: 21 Apr 2019) Maths Previous Year paper
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  1. (-5)2n - 1
  2. (-1)2n 5n+1
  3. (-1)2n – 1 5n+1
  4. (-1)n-1 5n+1

Answer (Detailed Solution Below)

Option 4 : (-1)n-1 5n+1
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धारणा:

यदि a1, a2, …., an एक गुणोत्तर श्रेणी है तो सामान्य पद निम्न द्वारा दिया जाता है: an = a × rn - 1 जहाँ a पहला पद है और r सार्व अनुपात है।

गणना:

दिया हुआ: 25, -125, 625, -3125, …….

यहाँ, पहला पद a = 25 और सार्व अनुपात r = -5।

जैसा कि हम जानते हैं कि, यदि a1, a2, …., an एक GP है तो सामान्य पद निम्न द्वारा दिया जाता है: an = a × rn - 1 जहाँ a 1ला पद है और r सार्व अनुपात है।

⇒ सामान्य पद है : an = 25 × (-5)n – 1 = (-1)n – 1 × 5n + 1

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