Question
Download Solution PDFC(n, 1) + C(n, 2) + _ _ _ _ _ + C(n, n) किसके बराबर है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
(1 + x)n = nC0 × 1(n-0) × x 0+ nC1 × 1(n-1) × x 1 + nC2 × 1(n-2) × x2 + …. + nCn × 1(n-n) × xn
G.P. का nवां पद an = arn−1 है
n पदों का योग = s =
n पदों का योग = s =
गणना:
C(n, 1) + C(n, 2) + _ _ _ _ _ + C(n, n)
⇒ nC1 + nC2 + ... + nCn
⇒ nC0 + nC1 + nC2 + ... + nCn - nC0
⇒ (1 + 1)n - nCo
⇒ 2n - 1 =
G.P योग = a ×
∴ 2n - 1 = 1 + 2 + 22 + ... +2n-1 जो हमें कुल में n पद देगा।
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