Question
Download Solution PDFदीर्घवृत्त
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
एक दीर्घवृत्त के मानक समीकरण को:
एक दीर्घवृत्त पर किसी बिंदु के केंद्रबिंदु की दूरी का योग स्थिरांक होता है और यह दीर्घवृत्त के प्रमुख अक्ष की लम्बाई के बराबर होता है।
यदि a > b है, तो PS + PS' = 2a = प्रमुख अक्ष है।
यदि b > a है, तो PS + PS' = 2b = प्रमुख अक्ष है।
गणना:
दिया गया है:
दीर्घवृत्त का समीकरण
यहाँ a2 = 4 और b2 = 9
⇒ a = 2 और b = 3
इसलिए प्रमुख अक्ष लम्बाई 2b वाले y - अक्ष पर है।
अब, केंद्रबिंदु की दूरी का योग = 2b = 2 × 3 = 6 इकाई
Last updated on Jun 20, 2025
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