त्रिभुज ABC में, ∠A = 60°, AB = 6 सेमी और AC = 4 सेमी। BC का मान ज्ञात कीजिए।

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  1. \(\frac{2}{\sqrt{7}}\) सेमी
  2. \(\frac{3}{\sqrt{5}}\) सेमी
  3. \(\frac{7}{\sqrt{7}}\) सेमी
  4. \(\frac{5}{\sqrt{5}}\) सेमी

Answer (Detailed Solution Below)

Option 1 : \(\frac{2}{\sqrt{7}}\) सेमी
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Detailed Solution

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दिया गया है:

त्रिभुज ABC में,

∠A = 60º

AB = 6 सेमी

AC = 4 सेमी

प्रयुक्त सूत्र:

कोज्या नियम का उपयोग करने पर:

BC2 = AB2 + AC2 - 2 × AB × AC × cos(∠A)

गणना:

मानों को प्रतिस्थापित करें:

AB = 6, AC = 4, cos(60º) = 1/2

⇒ BC2 = 62 + 42 - 2 × 6 × 4 × (1/2)

⇒ BC2 = 36 + 16 - 24

⇒ BC2 = 28

⇒ BC = √28

⇒ BC = √(4 × 7)

⇒ BC = 2√7

⇒ BC = (2/√7) सेमी

BC की सही लंबाई 2√7 सेमी है।

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